2m^2-32m+120=0

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Solution for 2m^2-32m+120=0 equation:


Simplifying
2m2 + -32m + 120 = 0

Reorder the terms:
120 + -32m + 2m2 = 0

Solving
120 + -32m + 2m2 = 0

Solving for variable 'm'.

Factor out the Greatest Common Factor (GCF), '2'.
2(60 + -16m + m2) = 0

Factor a trinomial.
2((6 + -1m)(10 + -1m)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(6 + -1m)' equal to zero and attempt to solve: Simplifying 6 + -1m = 0 Solving 6 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1m = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1m = 0 + -6 -1m = 0 + -6 Combine like terms: 0 + -6 = -6 -1m = -6 Divide each side by '-1'. m = 6 Simplifying m = 6

Subproblem 2

Set the factor '(10 + -1m)' equal to zero and attempt to solve: Simplifying 10 + -1m = 0 Solving 10 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1m = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1m = 0 + -10 -1m = 0 + -10 Combine like terms: 0 + -10 = -10 -1m = -10 Divide each side by '-1'. m = 10 Simplifying m = 10

Solution

m = {6, 10}

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